[maemo-developers] [maemo-developers] Measuring power consumption of 770
From: Larry Battraw lbattraw at gmail.comDate: Thu Mar 16 01:22:41 EET 2006
- Previous message: [maemo-developers] Measuring power consumption of 770
- Next message: [maemo-developers] Re: Measuring power consumption of 770
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
I concur; measuring the voltage and current simultaneously (And rapidly) is critical. I've tried these type of measurements before and it's not nearly as simple as you would think. A one ohm resistor is not a good idea-- it will drop too much voltage, causing the device to shutdown. Assuming wireless is active, it will be drawing roughly 500 mA, which translates to a .5V voltage drop, leading to the device seeing 3.2V which will cause issues. Likewise, 500 mA is only an average and the peak currents are likely to be much higher. I would suggest using a .1 ohm resistor, and to make sure that you measure the voltage across the resistor at the same points you feed the power through so you don't end up measuring the voltage drop of the wires as well. At .1 ohms, it won't take much to throw the measurements off. Larry On 3/15/06, Teemu Nikkilä <tnikkila at cc.hut.fi> wrote: > On Wednesday, 15. March 2006 13:44, Igor Stoppa wrote: > > If I'm proposing the battery, there's a reason ... > > Yes, this must be the least problematic way. > > > and no, i won't go > > any further, but anyway faking a battery is not the scope of this study, > > according to my understanding, so using a real one will be just ok. > > You just need to measure and record the cell voltage too to get the actual > power consumption. >
- Previous message: [maemo-developers] Measuring power consumption of 770
- Next message: [maemo-developers] Re: Measuring power consumption of 770
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]